Principles of Inheritance and Variation

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Question
CBSEENBI12002258

A colour blind man marries a woman with normal sight who has no history of colour blindness in her family. What is the probability of their grandson being colour blind?

  • 0.5

  • 1

  • Nil

  • 0.25

Solution

C.

Nil

When a colour blind (XCY) marries to a woman with normal sight (XX) who has no family history of colour blindness, all of their sons will be normal pure and all of their daughters will be carriers as shown below:

So in the next generation, the children of all of their son will be normal in all conditions(except the case in which the wife involved is not carrier neither colour blind). For carrier daughters.
(i) If they many to a normal man 50% of their grandsons will become colour blind as

(ii) If carrier daughter marries to a colour blind man 50% of their grandson will be colour blind along with 50% of the grand daughter while rest 50% of the grand daughters will be carriers as

So in both the above cases, the result shows 50% of grand sons will be colour blind which in terms of over all progress (son + daughter) comes as 25% thus confirming the probability as 0.25.

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Question
CBSEENBI12002739

A common test to find the genotype of a hybrid is by

  • crossing of one F2 progeny with male parent

  • crossing of one F2 progeny with female parent

  • studying the sexual behaviour of F1 progenies

  • crossing of one F1 progeny with male parent

Solution

D.

crossing of one F1 progeny with male parent

Test cross, crossing of F1 progeny to the recessive parent is used to find the genotype of the progeny.

Question
CBSEENBI11003735

A disease caused by an autosomal primary non-disjunction is

  • Down's syndrome

  • Klinefelter's syndrome

  • Turner's syndrome

  • Sickle cell anemia

Solution

A.

Down's syndrome

Down’s syndrome is caused by non-disjunction of 21st chromosome

Question
CBSEENBI12002239

A gene showing codominance has:

  • One allele dominant on the other

  • alleles tightly linked on the same chromosome

  • alleles that are recessive to each other

  • both alleles independently expressed in the heterozygote

Solution

D.

both alleles independently expressed in the heterozygote

A gene shows codominance when both alleles in heterozygous condition, express their traits independently instead of showing dominant-recessive relationship and such alleles are called codominant alleles. 

Question
CBSEENBI12002366

A human female with Turner's syndrome

  • has 45 chromosomes with XO

  • has one additional X - chromosome

  • exhibits male characters

  • is able to produce children with normal husband

Solution

A.

has 45 chromosomes with XO

Turner syndrome is a chromosomal condition that affects the development in females. The most common feature of Turner syndrome is short stature, which becomes evident by the age of about 5. An early loss of ovaries develop normally at first, but egg cells usually die prematurely and most ovarian tissue degenerates before birth. In other words, the absence of one of the X - chromosome i.e., 45 with XO (or 44 + XO).

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