Wave Optics

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Question
CBSEENPH12039511

A beam of unpolarized light of intensity I0 is passed through a Polaroid A and then through another polaroid B which is oriented so that its principal plane makes an angle of 45° relative to that of A.The intensity of the emergent light is

  • I0

  • I0/2

  • I0/4

  • I0/8

Solution

C.

I0/4

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Question
CBSEENPH12039527

A cylindrical tube, open at both ends, has a fundamental frequency, f, in the air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air-column is now

  • f

  • f/2

  • 3f/4

  • 2f

Solution

A.

f

Initially for open organ pipe, fundamental frequency,
straight v subscript straight o space equals space fraction numerator straight v over denominator 2 l end fraction space equals straight f
But when it is half dipped in water, then it becomes closed organ pipe of length l/2. In this case fundamental frequency.
straight v subscript straight c space equals space fraction numerator straight v over denominator 4 l end fraction space equals space fraction numerator straight v over denominator 4 begin display style l over 2 end style end fraction space equals space fraction numerator straight V over denominator 2 l end fraction space equals straight f

Question
CBSEENPH12039677

A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12 cm below the surface, the radius of this circle in cm is

  • 36 square root of 7
  • 36 divided by square root of 7
  • 36 square root of 5
  • 4 square root of 5

Solution

B.

36 divided by square root of 7 straight r equals fraction numerator straight h over denominator square root of straight mu squared minus 1 end root end fraction space equals space fraction numerator 36 over denominator square root of 7 end fraction

Question
CBSEENPH12039502

A green light is an incident from the water to the air – water interface at the critical angle (θ). Select the correct statement

  • The entire spectrum of visible light will come out of the water at various angles to the normal.

  • The spectrum of visible light whose frequency is less than that of green light will come out to the air medium

  • The spectrum of visible light whose frequency is more than that of green light will come out to the air medium.

  • The entire spectrum of visible light will come out of the water at an angle of 900 to the normal.

Solution

D.

The entire spectrum of visible light will come out of the water at an angle of 900 to the normal.

As the frequency of visible light increases refractive index increases. With the increase of refractive index critical angle decreases. So that light having a frequency greater than green will get total internal reflection and the light having the frequency less than green will pass to air.

Question
CBSEENPH12039593

A mixture of light, consisting of wavelength 590 nm and an unknown wavelength, illuminates Young's double slit and gives rise to two overlapping interference patterns on the screen. The central maximum of both lights coincide. Further, it is observed that the third bright fringe of known light coincides with the 4th bright fringe of the unknown light. From this data, the wavelength of the unknown light is

  • 393.4 nm

  • 885.0 nm

  • 442.5 nm

  • 776.8 nm

Solution

C.

442.5 nm

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