Exponents and Powers

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Question
CBSEENMA8002605

Find the multiplicative inverse of the following.
(i) 2–4            (ii) 10–5         (iii) 7–2    (iv) 5–3   (v) 10–100

Solution

(i) The multiplicative inverse of 2–4 is 24.

(ii) The multiplicative inverse of 10–5 is 105
(iii) The multiplicative inverse of 7–2 is 72.

(iv) The multiplicative inverse of 5–3 is 53.

(v) The multiplicative inverse of 10–100 is 10100.

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Question
CBSEENMA8002608

Simplify and write in exponential form.

(–2)–3 x (–2)–4

Solution

(–2)–3 x (–2)–4  = (-2)(-3) + (-4)                  [∵ space space straight a to the power of straight m cross times straight a to the power of straight n equals straight a to the power of straight m plus straight n end exponent]
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#6 {main}</pre> or  fraction numerator 1 over denominator left parenthesis negative 2 right parenthesis to the power of 7 end fraction

Question
CBSEENMA8002609

Simplify and write in exponential form.

p3 x p–10

Solution

p3 x p–10= left parenthesis straight p right parenthesis to the power of 3. space left parenthesis negative 10 right parenthesis end exponent space equals left parenthesis straight p right parenthesis to the power of negative 7 end exponent or space fraction numerator 1 over denominator left parenthesis 10 right parenthesis to the power of 7 end fraction

Question
CBSEENMA8002611

Simplify and write in exponential form.

32 x 3–5 x 36

Solution

32 x 3–5 x 36 = 3 to the power of 2 plus left parenthesis negative 5 right parenthesis plus 6 end exponent space equals space 3 to the power of 8 minus 5 end exponent equals 3 cubed