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Wave Particle Duality: Matter Waves

Question
ICSEENIPH12029761

What is the relation between wavelength and momentum of moving particles?

Solution

straight p space equals space straight h over straight lambda ; 
where, 
p = momentum 
h = planck's constant 
straight lambda = wavelength

Question
ICSEENIPH12029837

Calculate the energy released when an electron annihilates a positron.

Solution

Energy of equivalent of mass of electron and positron.

Eo = moC2 
    = (9.1 x 10-31 X3 x 108 )
   
    = 8.2 space straight x space 10 to the power of negative 14 end exponent space equals space fraction numerator 8.2 space straight x space 10 to the power of negative 14 end exponent over denominator 1.6 space straight x space 10 to the power of negative 13 end exponent end fraction space equals space 0.51 space MeV
Energy released = 0.51 x 2 = 1.02 MeV

Question
ICSEENIPH12029845

Which one of the following graphs in Figure 1 represents variation of de Broglie wavelength (λ) of particle having linear momentum p: 
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Solution

D.

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Question
ICSEENIPH12029903

De Broglie wavelength of electrons of kinetic energy E is λ. What will be its value if kinetic energy of electrons is made 4E?

Solution

De Broglie’s wavelength of electron = λ

Let the new wavelength be λ2

K.E. of electrons = E

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