The emf ‘E’ of a thermocouple varies with the temperature θ (in degree C) of the hot junction (cold junction at 0°C) as E = 15 q 0.05 q^2.
Determine the neutral temperature.

Solution

Given, E =15 θ - 0.05 θ^{2

$dE over dθ space equals space 15 space minus space 2 space straight x space 0.05 space straight theta dE over dθ space equals space 15 space minus space 0.1 space straight theta at space space straight theta space equals space straight theta subscript straight n dE over dθ space equals space 0 space therefore space 15 space minus space 0.1 space space straight theta subscript straight n space equals space 0 15 space equals space 0.1 space space straight theta subscript straight n space straight theta subscript straight n space equals space fraction numerator 15 over denominator 0.1 end fraction space straight theta subscript straight n space equals space 150 space to the power of straight o space straight C$}

This is the required neutral temperature.

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Transient Current

The emf ‘E’ of a thermocouple varies with the temperature θ (in degree C) of the hot junction (cold junction at 0°C) as E = 15 q 0.05 q^2.
Determine the neutral temperature.

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Entrance Exams Preparation

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For Daily Free Study Material Join wiredfaculty

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Transient Current

The emf ‘E’ of a thermocouple varies with the temperature θ (in degree C) of the hot junction (cold junction at 0°C) as E = 15 q 0.05 q2.Determine the neutral temperature.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The emf ‘E’ of a thermocouple varies with the temperature θ (in degree C) of the hot junction (cold junction at 0°C) as E = 15 q 0.05 q^2.
Determine the neutral temperature.