States Of Matter: Structure And Properties Solid State

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Question
ICSEENICH12028848

Copper has the face centred cubic structure. The coordination number of each ion is:

  • 4

  • 12

  • 14

  • 8

Solution

A.

4

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Question
ICSEENICH12028863

(i) What is Schottky defect in a solid?

(ii) A bcc element (atomic mass 65) has a cell edge of 420 pm. Calculate its density in gms / cm3.

Solution

i) When in a crystal lattice cations and anions both are missing from their normal site leaving holes then the defect is known as Schottky defect. For example KBr, NaCl, KCl.

ii) We have given,
Z = 2
cell edge = 420 pm
NA = 6.023 x 1023 
Mass = 65 g
density = ? 
space density space left parenthesis straight d right parenthesis space space equals space fraction numerator straight Z space straight x space straight M over denominator straight N subscript straight A space straight x space straight a cubed end fraction

equals space fraction numerator 2 space straight x space 65 over denominator 6.023 space straight x space 10 to the power of 23 space straight x space left parenthesis 420 space straight x space 10 to the power of negative 10 end exponent right parenthesis cubed end fraction space equals space 2.91 space straight g space cm to the power of negative 3 end exponent

Question
ICSEENICH12028902

i) What are F-centres in an ionic crystal?

(ii) Why are crystals having F-centres paramagnetic?

Solution

(i) Ionic compounds having non-stoichiometric defects, anionic vacancies are occupied by electrons. These are known as F-centres. These electrons are delocalised and responsible for importing colours to crystals.

(ii) Free impaired electrons occupying anionic vacancies spin in a particular direction result in the magnetic moment and ionic crystals with F-centres. So, they show paramagnetic behaviour.

Question
ICSEENICH12028907

For a crystal of diamond, state:

(i) The hybridisation of the carbon atom.

(ii) The coordination number of each carbon atom.

(iii) The type of lattice in which it crystalises.

(iv) The number of carbon atoms present per unit cell.

Solution

 (i) Sp3 hybridization

(ii) Coordination number = 4

(iii) Lattice type = Giant network type with fcc arrangement of c-atoms.

(iv) Number of particles per unit cell = 4