Question

Define cryoscopic constant.

Solution

Cryoscopic constant is defined as the Molal depression constant Or it may be defined as the depression in freezing point when one mole of non-volatile solute is dissolved in one kilogram of solvent. Its units K Kg mol^-1

Question

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Match the following:

A. Colligative property (i) Polysaccharide
B. Nicol prism (ii) Aldol condensation
C. Activation energy (iii) Ammonia
D. Starch (iv) Polarimeter
E. Acetaldehyde (v) Arrhenius equation

Solution

A.

Colligative property

(i)

Ammonia

B.

Nicol prism

(ii)

Polarimeter

C.

Activation energy

(iii)

Arrhenius equation

D.

Starch

(iv)

Polysaccharide

E.

Acetaldehyde

(v)

Aldol condensation

Question

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Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water of prevent it from freezing at -6°C. (K_ffor H₂0 = 1.85 K mole^-1 kg)

Solution

W =?
W = 4Kg =4000 gm
K_f =1.85
Freezing point of pure water =0⁰ C

$increment straight T subscript straight f space equals space 0 minus left parenthesis negative 6 right parenthesis space equals space 0 plus 6 space equals 6 degree space straight C Molecular space Mass CH subscript 2 OH vertical line CH subscript 2 OH space space space equals 62 straight W subscript 1 space equals space fraction numerator increment straight T subscript straight f space straight x space straight M space straight x space straight W subscript 2 over denominator 1000 space straight x space 1.85 end fraction straight W subscript 1 space equals fraction numerator space 62 space straight x space 4000 straight x space 6 over denominator 1000 space straight x space 1.85 end fraction space equals 804.32 space gm$

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The freezing point of a solution containing 0.3 gms of acetic acid in 30 gms of benzene is lowered by 0.45K. Calculate the Van’t Hoff factor. (at. wt. of C = 12, H = 1, 0 =16, K_f for benzene = 5.12K kg mole^-1)

Solution

$increment straight T subscript straight f space equals space straight i space straight x space straight K subscript straight f space straight x space straight m space............1 where space straight m space can space be space straight m space equals space fraction numerator 1000 space straight x space straight w over denominator straight M space straight x space straight W end fraction Putting space value space of space straight m space in space equation space 1 straight i space equals space fraction numerator increment straight T subscript straight f space straight x space straight M space straight x space straight W over denominator 1000 space straight x space straight K subscript straight f space straight x space straight w end fraction space equals fraction numerator 0.45 space straight x space 60 space straight x space 30 space over denominator 1000 straight x space 5.12 space straight x space 0.3 end fraction space equals space.527 space$

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Relative Molecular Mass And Mole

Define cryoscopic constant.

Match the following:

A. Colligative property (i) Polysaccharide
B. Nicol prism (ii) Aldol condensation
C. Activation energy (iii) Ammonia
D. Starch (iv) Polarimeter
E. Acetaldehyde (v) Arrhenius equation

Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water of prevent it from freezing at -6°C. (K_ffor H₂0 = 1.85 K mole^-1 kg)

The freezing point of a solution containing 0.3 gms of acetic acid in 30 gms of benzene is lowered by 0.45K. Calculate the Van’t Hoff factor. (at. wt. of C = 12, H = 1, 0 =16, K_f for benzene = 5.12K kg mole^-1)

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

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A. Colligative property	(i) Polysaccharide
B. Nicol prism	(ii) Aldol condensation
C. Activation energy	(iii) Ammonia
D. Starch	(iv) Polarimeter
E. Acetaldehyde	(v) Arrhenius equation

For Daily Free Study Material Join wiredfaculty

WhatsApp Group

Download Android App

Ncert Book Download

Relative Molecular Mass And Mole

Define cryoscopic constant.

Match the following: A. Colligative property (i) Polysaccharide B. Nicol prism (ii) Aldol condensation C. Activation energy (iii) Ammonia D. Starch (iv) Polarimeter E. Acetaldehyde (v) Arrhenius equation

Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water of prevent it from freezing at -6°C. (Kf for H20 = 1.85 K mole-1 kg)

The freezing point of a solution containing 0.3 gms of acetic acid in 30 gms of benzene is lowered by 0.45K. Calculate the Van’t Hoff factor. (at. wt. of C = 12, H = 1, 0 =16, Kf for benzene = 5.12K kg mole-1)

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Match the following:

A. Colligative property (i) Polysaccharide
B. Nicol prism (ii) Aldol condensation
C. Activation energy (iii) Ammonia
D. Starch (iv) Polarimeter
E. Acetaldehyde (v) Arrhenius equation

Ethylene glycol is used as an antifreeze agent. Calculate the amount of ethylene glycol to be added to 4 kg of water of prevent it from freezing at -6°C. (K_ffor H₂0 = 1.85 K mole^-1 kg)

The freezing point of a solution containing 0.3 gms of acetic acid in 30 gms of benzene is lowered by 0.45K. Calculate the Van’t Hoff factor. (at. wt. of C = 12, H = 1, 0 =16, K_f for benzene = 5.12K kg mole^-1)