Magnetic Field And Earths Magnetism

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Question
ICSEENIPH12029753

 Name any one instrument which works on the principle of tangent law in magnetism.

Solution

Deflection magnetometre, tangent galvanometer.

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Question
ICSEENIPH12029801

Write an expression of magnetic flux density ‘B’ at a point in end - on position or an axial position of a magnetic dipole, (Derivation not required.)

Solution


Magnetic flux density at the axial position


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Question
ICSEENIPH12029820

Adjecent figure shows a point P near a long conductor XY carrying a current I. MN is a short current carrying conductor, kept at the point P, parallel to the conductor XY.

(i) What is the direction of magnetic flux density ‘B’ at the point P due to the current flowing through XY?

(ii) What is the direction of the force experienced by the conductor MN due to the current flowing through XY?

Solution

(i) Direction of the magnetic flux density is perpendicular to the surface and inwardly directed to the plane of the paper.

(ii) Direction of force experienced by the conductor MN is towards conductor XY.

Question
ICSEENIPH12029913

A small magnetic needle NS having magnetic dipole moment straight P with rightwards harpoon with barb upwards on top subscript m is kept in two uniform and perpendicular magnetic fields straight B with rightwards harpoon with barb upwards on top subscript F space a n d space B with rightwards harpoon with barb upwards on top subscript H as shown below:

 

(i) What is the effect of each of the magnetic fieldsstraight B with rightwards harpoon with barb upwards on top subscript F space a n d space B with rightwards harpoon with barb upwards on top subscript H on the needle?

(ii) When the needle is in equilibrium, obtain an expression for an angle θ made by the needle with straight B with rightwards harpoon with barb upwards on top subscript F in terms straight B with rightwards harpoon with barb upwards on top subscript F space a n d space B with rightwards harpoon with barb upwards on top subscript H of only.

Solution

(i)
The needle is under the action of two perpendicular and uniform magnetic field Band Bh.
This will set a couple of force on the needle as BF out in a direction opposite to BH.
This will tend to rotate the needle.

(ii)
When the needle is in equilibrium position then straight P with rightwards harpoon with barb upwards on top subscript m will make an angle θ with the direction of BH.
Let the pole strength of the N and S be the m.
Then moment of couple due to field BF = m x BH x SA
Moment of couple due to field BH = m x BF x NA

In the equilibrium position the moments of two couples are equal.

M x BH x SA = m x BF x NA  
  SA / NA x BH = BF

BH = BF   

 BF = BH tan θ
Hence proved.