Magnetic Effect Of Current

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Question
ICSEENIPH12029748

The Biot Savart’s Law in vector form is:
  • dB with rightwards harpoon with barb upwards on top space equals space fraction numerator mu subscript o over denominator 4 pi end fraction space fraction numerator d I space left parenthesis I with rightwards harpoon with barb upwards on top space x space r with rightwards harpoon with barb upwards on top right parenthesis over denominator r cubed end fraction
  • dB with rightwards harpoon with barb upwards on top space equals space fraction numerator mu subscript o over denominator 4 pi end fraction space fraction numerator straight I space left parenthesis dl with rightwards harpoon with barb upwards on top space x space r with rightwards harpoon with barb upwards on top right parenthesis over denominator r cubed end fraction
  • dB with rightwards harpoon with barb upwards on top space equals space fraction numerator mu subscript o over denominator 4 pi end fraction space fraction numerator straight I space left parenthesis straight r with rightwards harpoon with barb upwards on top space straight x space dl with rightwards harpoon with barb upwards on top right parenthesis over denominator r cubed end fraction
  • dB with rightwards harpoon with barb upwards on top space equals space fraction numerator mu subscript o over denominator 4 pi end fraction space fraction numerator straight I space left parenthesis dl with rightwards harpoon with barb upwards on top space x space r with rightwards harpoon with barb upwards on top right parenthesis over denominator r squared end fraction

Solution

B.

dB with rightwards harpoon with barb upwards on top space equals space fraction numerator mu subscript o over denominator 4 pi end fraction space fraction numerator straight I space left parenthesis dl with rightwards harpoon with barb upwards on top space x space r with rightwards harpoon with barb upwards on top right parenthesis over denominator r cubed end fraction

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Question
ICSEENIPH12029754

State the SI unit of magnetic dipole moment.

Solution

Ampre-metre2

Question
ICSEENIPH12029773

Figure below shows two infinitely long and thin current carrying conductors X and Y kept in vacuum, parallel to each other, at a distance ‘a’. 

(i) How much force per unit length acts on the conductor Y due to the current flowing througn X? Write your answer in terms of fraction numerator straight mu subscript straight o over denominator 4 straight pi end fraction comma space I subscript 1 comma space I subscript 2 space a n d space a

 

(ii) Define ampere, in terms of froce between two current carrying conductors. 

Solution

i) Force applied per unit length is given by, 
     straight F over straight I space equals space fraction numerator mu subscript o over denominator 2 pi end fraction space fraction numerator I subscript 1 space I subscript 2 over denominator space a end fraction
ii) One ampere is the current which when flowing in each of two infinitely long parallel conductors 1 m apart in vaccum produces between them a force of exactly 2 x 10-10 Newton per metre of length. 

Question
ICSEENIPH12029843

When a charged particle is projected perpendicular to a uniform magnetic field, it describes a circular path in which:
  • its speed remains constant 
  • its velocity remains constant.
  • its velocity remains constant.
  • its kinetic energy increases.

Solution

A.

its speed remains constant