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Gauss Theorem

Question
ICSEENIPH12030027

State Gauss’s theorem.

Solution

Gauss’s theorem : It states that the electric flux fE, through any closed surface is 1/Î0 times the total charge q enclosed by the surface.
Mathematically, 
straight ϕ subscript straight E space equals space straight E with rightwards harpoon with barb upwards on top space. space ds with rightwards harpoon with barb upwards on top space equals space straight q over straight epsilon subscript straight o

Question
ICSEENIPH12030094

An infinite line charge produces a field of 9 x 104 NC-1 at a distance of 2 cm. Calculate the linear charge density.   

Solution

For infinite long line charge,
WiredFaculty 
We have, 

E = 9 x io4 N/C

r = 2 cm = 2 x 10-2 m
Hence, 
WiredFaculty 

Question
ICSEENIPH12030237

A short electric dipole (consists of two point charges +q and -q) is placed at the centre O and inside a large cube (ABCDEFGH) of length L, as shown in the figure below. The electric flux, remaining through the cube is:

WiredFaculty
  • fraction numerator straight q over denominator 4 πε subscript straight o straight L end fraction
  • Zero

  • fraction numerator straight q over denominator 2 πε subscript straight o straight L end fraction
  • fraction numerator straight q over denominator 3 πε subscript straight o straight L end fraction

Solution

B.

Zero

Since, it is an electric dipole, the net charge enclosed by the surface is zero. Therefore, according to Gauss's law, electric flux through the cube will be zero.