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Gauss’s theorem : It states that the electric flux fE, through any closed surface is 1/Î0 times the total charge q enclosed by the surface.
Mathematically, 
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For infinite long line charge,
We have,
E = 9 x io4 N/C
r = 2 cm = 2 x 10-2 m
Hence, 
A short electric dipole (consists of two point charges +q and -q) is placed at the centre O and inside a large cube (ABCDEFGH) of length L, as shown in the figure below. The electric flux, remaining through the cube is:
Zero
B.
Zero
Since, it is an electric dipole, the net charge enclosed by the surface is zero. Therefore, according to Gauss's law, electric flux through the cube will be zero.
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Mock Test Series
