Chemistry of Transition And Inner-Transition Elements

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Question
ICSEENICH12028872

 In the extraction of zinc from zinc how oxide is converted to zinc.  

(i) Give an equation to show how zinc oxide is converted to zinc.

(ii) How is impure zinc finally electro-refined.

Solution

(i)ZnO+C → Zn+CO

(ii) Impure zinc is electro-refined by using impure zinc as an anode, pure zinc as a cathode and an aqueous solution of ZnSO4 as electrolyte containing a little H2SO4.
Cathode → Zn2+ + 2e- → Zn
Anode → Zn → Zn2+ + 2e

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Question
ICSEENICH12028873

Explain why:

(i) Transition elements form coloured compounds.

(ii) Interhalogen compounds are more reactive than their constituent elements.

(iii) Cu+ is diamagnetic but Cu2+ is paramagnetic. (Z = 29).

Solution

(i) Due to the presence of unpaired electrons in d-orbitals and empty d-orbitals. Gives rise to possibility of d-d transition.
(ii) X—Y bonds are weaker than X—X and Y—Y bonds/Polar nature of X—Y bonds/Less overlapping of orbitals in X—Y bond.
(iii) Cu1+ has no unpaired electrons, hence diamagnetic. Cu2+ has unpaired electrons, hence paramagnetic. [Cu→29→1s2 , 2s2 , 2p6 , 3s2 , 3p6 , 4s1 , 3d10]
[Cu1+→28→1s2 , 2s2 , 2p6 , 3s2 , 3p6 , 3d10; d-orbital fully filled]
all electron in Cu1+ is paired.
[Cu2+→27→1s2 , 2s2 , 2p6 , 3s2 , 3p6 , 4s1 , 3d9 ; d-orbital partially filled 1 unpaired electron].

Question
ICSEENICH12028889

Give one example (equation) of a homogeneously catalysed reaction and name the catalyst.

Solution

Hydrolysis of ethyl acetate to give ethanol and acetic acid is catalyzed by dilute H2SO4.

stack CH subscript 3 COOC subscript 2 straight H subscript 5 with Ethyl space acetate below space plus space stack straight H subscript 2 straight O with Water below space rightwards arrow from dil space straight H subscript 2 SO subscript 4 to catalyst of space stack CH subscript 3 COOH with Acetic space acid below space plus stack straight C subscript 2 straight H subscript 5 OH with Ethanol below

Question
ICSEENICH12028892

What is the electronic configuration of chromium atom (Z = 24)? Give a reason for your answer.

Solution

The electronic configuration of Cr (24) is 1s2, 2s2p6, 3s2p6d5,4s1.
This is because an electronic configuration with half-filled and completely filled orbitals is more stable. Cr has 3d orbitals half filled configuration which is more stable than normally expected i.e 3d4 4s2.