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Mole Concept And Stoichiometry

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Question
ICSEENICH10003664
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Choose the most appropriate answer for the following:

Which of the following would weigh the least?

A) 2 gram atoms of nitrogen.

B) 1 mole of silver

C) 22.4 Litres of oxygen gas at 1 atomspheric pressure and 273K

D) 6.02  x 1023 atoms of carbon.

[ atomic masses : Ag (108, N =14, O=16, C=12]

Solution

D) 6.02  x 1023 atoms of carbon.

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Question
ICSEENICH10003665
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(c) complete the following calculation. Show working for complete credit:

I) calculate the mass of calcium that will contain the same number of atom as are present in 3.2 gm of sulphur.

[atomic masses : S= 32, Ca= 40]

Solution

32 space gm space of space sulphur space equals space 1 space mole space 3.2 space gm space of space sulphur space equals 1 over 32 straight x 3.2 equals space 0.1 space Moles at space mass space of space Calcium space equals 40 therefore space mass space of space 0.1 space mole space of space Ca space equals 40 space straight x space 0.1 space equals space 4 gm

Question
ICSEENICH10003666
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complete the following calculation. Show working for complete credit:

if 6 liters of hydrogen and 4 liters of chlorine are mixed and exploded and if water is added to the gases formed, find the volume of the residual.

Solution

straight H subscript 2 space plus Cl subscript 2 space rightwards arrow space 2 HCl 1 space space space space space colon space 1 space space space space space space colon space 2 If space 1 space vol. space of space Cl subscript 2 space combine space with space 1 space vol. space of space straight H subscript 2 Then space 4 straight l space of space Cl subscript 2 space combine space with space 4 straight l space of space straight H subscript 2 Vol. space of space straight H subscript 2 space equals 6 straight l Vol space of space residual space space equals 6 minus 4 space space equals 3 equals 2 straight l space of space straight H subscript 2 space in space the space residual space gas

Question
ICSEENICH10003667
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Complete the following calculation. Show working for complete credit:

If the empirical formula of a compound is CH and it has a vapour density of 13 find the molecular formula of the compound.

Solution

Molecular space formula space equals CH space space space space space space space straight V. straight D space equals space 13 Mol. space mass space equals space 2 space straight x space straight V. straight D space equals space 2 straight X 13 space equals 26 Empirical space forumula space weight space of space CH space equals 12 plus 1 space equals 13 straight n fraction numerator Mol. space Mass over denominator Emp. space formula space mass end fraction space equals 26 over 13 space equals 2 Molecular space formula space equals space Emp. space formula space straight x space 2 space space equals space CH space straight x space 2 space equals space straight C subscript 2 straight H subscript 2

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