$$\begin{gathered} \mathrm{Mean} = \frac{\mathrm{Sum} \mathrm{of} \mathrm{all} \mathrm{observations}}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{observations}} \\ \therefore 68 = \frac{45 + 52 + 60 + \mathrm{x} + 69 + 70 + 26 + 81 + 94}{9} \\ \Rightarrow 68 = \frac{497 + \mathrm{x}}{9} \\ \Rightarrow 612 = 497 + \mathrm{x} \\ \Rightarrow \mathrm{x} = 612 - 497 \\ \Rightarrow \mathrm{x} = 115 \end{gathered}$$

Data in ascending order

26,  45,  52,  60,  69,  70,  81,  94,  115

$$\begin{gathered} \mathrm{Since} \mathrm{the} \mathrm{number} \mathrm{of} \mathrm{observations} \mathrm{is} \mathrm{odd}, \mathrm{the} \mathrm{median} \mathrm{is} \mathrm{the} {\left( \frac{\mathrm{n} + 1}{2} \right)}^{\mathrm{th}} \mathrm{observation} \\ \Rightarrow \mathrm{Median} = {\left( \frac{9 + 1}{2}\right)}^{\mathrm{th}} \mathrm{observation} = 5^{\mathrm{th}} \mathrm{observation} \end{gathered}$$

Hence, the median is  69.

( i )  Median = ${\left( \frac{\mathrm{n} }{2 }\right)}^{\mathrm{th}} \mathrm{term} = {\left( \frac{160}{2} \right)}^{\mathrm{th}} \mathrm{term} = {80}^{\mathrm{th}} \mathrm{term}$

Through mark  80  on y-axis, draw a horizontal line which meets the ogive drawn at point  Q.

Through  Q,  draw a vertical line which meets the  x-axis at the mark of  43.

$\Rightarrow$ Median =  43.

( ii ) Since the number of terms = 160

$$\begin{gathered} \mathrm{Lower} \mathrm{quartile} ( {\mathrm{Q}}_1 ) = {\left(\frac{160}{4}\right)}^{\mathrm{th}} \mathrm{term} = {40}^{\mathrm{th}} \mathrm{term} = 28. \\ \mathrm{Upper} \mathrm{quartile} ( {\mathrm{Q}}_3 ) = {\left(\frac{3 \mathrm{x} 160}{4}\right)}^{\mathrm{th}} \mathrm{term} = {120}^{\mathrm{th}} \mathrm{term} = 60. \\ \therefore \mathrm{Inter}-\mathrm{quartile} = {\mathrm{Q}}_3 - {\mathrm{Q}}_1 \\ = 60 - 28 \\ = 32. \end{gathered}$$

( iii ) Since  85 %  scores  =  85 %  of  100 = 85

Through mark for  85  on  x-axis, draw a vertical line which meets the ogive drawn at point  B.

Through the point  B,  draw a horizontal line which meets the  y-axis at the mark of  150.

$\Rightarrow$ Number of shooters who obtained more than  85 %  score = 160 - 150 =  10.