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Current Electricity

Question
ICSEENIPH10005542

What happens to the resistivity of semi-conductors with the increase of temperature? 

Solution

The resistivity of a semiconductor decreases with increase in temperature. 

Question
ICSEENIPH10005543

Find the equivalent resistance between points A and B. 

WiredFaculty

Solution

Let 12 straight capital omega, 6 straight capital omega and 4straight capital omega b are connected in parallel. 
Therefore, equivalent resistance is, 

fraction numerator 1 over denominator straight R subscript straight P space space end fraction equals space 1 fourth plus space 1 over 6 plus space 1 over 12 equals space fraction numerator 3 plus 2 plus 1 over denominator 12 end fraction equals space 6 over 12 equals space 1 half
That is, 
straight R subscript straight P space equals space 2 space straight capital omega

Question
ICSEENIPH10005544

The relationship between the potential difference and the current in a conductor is stated in the form of a law.

i) Name the law.

ii) What does the slope of V-I graph for a conductor represent?

iii) Name the material used for making the connecting wire. 

Solution

i) Ohm’s Law.

ii) The resistance of the conductor.

iii) Copper because it has less resistance.

Question
ICSEENIPH10005545

A cell of emf 2 V and internal resistance 1.2  is connected with an ammeter of resistance 0.8  and two resistors of 4.5  and 9 is shown as in the diagram below:

WiredFaculty

i) What would be the reading on the ammeter?

ii) What is the potential difference across the terminals of the cell?

Solution

Given, 
E = 2 V, r = 1.2 , R = external resistance

Let 4.5 straight capital omega  and 9 straight capital omega are connected in parallel, then equivalent resistance becomes,
1 divided by straight R subscript straight P space end subscript space equals space 1 divided by 4.5 plus space space 1 divided by 9 space
1 over R subscript P equals space fraction numerator 2 plus 1 over denominator 9 end fraction equals space 3 over 9 equals space 1 third
RP = 3 straight capital omega
Now, 0.8 straight capital omega, and RP resistance in series, then total resistance is, 
straight R space equals space 3 space plus space 0.8 space equals space 3.8 space straight capital omega
i) Current in 0.8 straight capital omega  resistance, I = Error converting from MathML to accessible text.
ii) Terminal voltage, V = E – I r = 2 – 0.4 × 1.2 = 2 – 0.48 = 1.52 Volt