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Calorimetry

Question
ICSEENIPH10005552

Rishi is surprised when he sees water boiling at 115o C in a container. Give reasons as to why water can boil at the above temperature. 

Solution

Water might have some impurities (e.g., salt dissolved in it. Because the boiling point of liquid (Water) increases by the addition of impurities in it. 

Question
ICSEENIPH10005553

i) Name a gas caused by the Greenhouse effect.

ii) Which property of water makes it an effective coolant? 

Solution

i) Carbon-di-oxide

ii) High specific heat capacity.

Question
ICSEENIPH10005554

i) Water in lakes and ponds do not freeze at once in cold countries. Give a reason in support for your answer.

ii) What is the principle of calorimetry?

iii) Name the law on which the principle is based.

iv) State the effect of an increase of impurities on the melting point of ice. 

Solution

i) The specific latent heat of fusion of ice is sufficiently high (336 J g-1 ) so as to freeze water, a large quantity of heat has to be withdrawn, hence it freezes slowly.

ii) Heat energy lost by the hot body is equal to the heat energy gained by the cold body. This is called the principle of calorimetry. For this, hot and the cold body should be kept in close contact and there is no exchange of heat from the surroundings.

iii) Law of conservation of energy.

iv) The melting of ice decreases by increasing of impurities in it. 

Question
ICSEENIPH10005555

A refrigerator converts 100 g of water at 20o C to ice at -10o C in 35 minutes. Calculate the average rate of heat extraction in terms of watts.

Given: Specific heat capacity of ice = 2.1 J g-10o C-1

Specific heat capacity of water = 4.2 J g-10o C-1

Specific Latent Heat of Fusion of ice = 336 J g-1

Solution

Mass of water = 100 g = 0.1 kg
Temperature of water = 20o C

Amount of heat extracted to convert water from 20o C to 0o C is, 
straight Q subscript 1 space equals space mC subscript water increment straight t

      = 0.1 x 4200 x (20-0)
      = 8400 J
Amount of heat extracted to convert water at 0 degree C to zero degree ice is,
Error converting from MathML to accessible text.
Amount of heat extracted to convert ice at 0o C to ice at -10o C is,
straight Q subscript 3 space equals space mL subscript ice increment straight t space space
     Error converting from MathML to accessible text.
Total heat (Q) = Q1 + Q2+ Q

                   = 8400+ 33600+ 2100
                   = 44100 J
Therefore,
      Q = Pt

rightwards double arrow space straight P space equals space straight Q over straight t 

Powerequals fraction numerator 44100 over denominator 35 space straight x space 60 end fraction space equals space 44100 over 21000 equals 21 over 10