Sponsor Area

Statistics

Question
CBSEENMA9003243

A traffic signal board, indicating ‘SCHOOL AHEAD’, is an equilateral triangle with side ‘a’. Find the area of the signal board, using Heron’s formula. If its perimeter is 180 cm, what will be the area of the signal board?

Solution

'a'   =  a
'b'   =  a
'c'   =  a
WiredFaculty
Area of the signal board
WiredFaculty
Perimeter = 180 cm
rightwards double arrow   'a' + 'b' + 'c' = 180
rightwards double arrow   a + a + a = 180
rightwards double arrow              3a = 180
WiredFaculty
rightwards double arrow space space space    a = 60  cm
therefore  Area of the signal board equals fraction numerator square root of 3 over denominator 4 end fraction straight a squared
           equals fraction numerator square root of 3 over denominator 4 end fraction left parenthesis 60 right parenthesis squared equals 900 square root of 3 space cm squared
Alternatively,
     space space space space space straight s space equals fraction numerator 3 straight a over denominator 2 end fraction equals 3 over 2 left parenthesis 60 right parenthesis equals 90 space cm
Area of the signal board
    WiredFaculty

Question
CBSEENMA9003244

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see figure). The advertisements yield an earning of र5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

WiredFaculty

Solution

a =122 m
b = 22 m
c = 120 m
WiredFaculty
 WiredFaculty

1 year =12 months
V Rent for 12 months per m2= र 5000

therefore space   Rent for 1 month per m2 =  र5000 over 2
therefore   Rent for 3 months of 1320 m2
                equals space र 5000 over 12 cross times 3 equals space र space 1250

therefore space space  Rent for 3 months of 1320 m2
            = र (1250 x 1320)
            = र 1650000.

Question
CBSEENMA9003245

There is a slide in a park. One of its side walls has been painted in some colour with a message “KEEP THE PARK GREEN AND CLEAN”. If the sides of the wall are 15 m, 11 m and 6 m, find the area painted in colour.

WiredFaculty

Solution

a = 15 m 
b = 11 m 
c = 6 m
WiredFaculty
therefore    Area painted in colour
    WiredFaculty

Question
CBSEENMA9003246

Find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 cm. 

Solution

 a = 18 cm
b = 10 cm Perimeter - 42 cm
⇒ a + b + c = 42
⇒ 18 + 10 + c = 42
⇒ 28 + c = 42
⇒    c = 42 – 28
⇒    c = 14 cm
 space space space space space space space space space space space space space straight s equals 42 over 2 equals 21 space cm
therefore space space space space space Area of the triangle 
       WiredFaculty