Sponsor Area

Playing with Numbers

Question
CBSEENMA8002717

Write the following numbers in generalized form.

(i) 25 (ii) 73 (iii) 129 (iv) 302

 

Solution

(i)       25 = 20 + 5
               = 10 x 2 + 5 x 1 = 10 x 2 + 5
(ii)       73 = 70 + 3
                = 10 x 7 + 3 x 1 = 10 x 7 + 3
(iii)      129 = 100 + 20 + 9
                = 100 x 1 + 20 x 2 + 1 x 9 = 100 x 1 + 10 x 2 + 9
(iv)       302 = 100 x 3 + 10 x 0 + 1 x 2 = 300 + 0 + 2

Question
CBSEENMA8002719

Write the following in the usual form.

(i) 10 x 5 + 6             (ii)  100 x 7 + 10 x 1 + 8        (iii) 100 x a + 10 x c + b

Solution

(i) 10 x 5 + 6 = 50 + 6 = 56
(ii) 100 x 7 + 10 x 1 + 8 = 700 + 10 + 8 = 718
(iii) 100 x a + 10 x c + b = 100 a + 10c + b = WiredFaculty

Question
CBSEENMA8002726

Check what the result would have been if sundaram had chosen the numbers shown below. 1. 27 2. 39 3. 64 4. 17

Solution

1.                      Chosen number = 27
         Number with reversed digits = 72
            Sum of the two numbers  = 27 + 72 = 99
Now,                                   99  = 11[9]
                                              = 11[2 + 7]
                                              = 11(Sum of the digits of the chosen number)

2.                         Chosen number = 39
            Number with reversed digits = 93
                Sum of the two numbers = 39 + 93 = 132
Now,                              132 + 11 = 12
i,e,                                 132 = 11[12]
                                           = 11 [ 3 + 9]
                                           = 11 [ Sum of the digits of the chosen number]            

3.                                     Chosen number = 64
                       Number with reversed digits  = 46
                                                    Sum   = 64 + 46 = 110
Now,                                                110 = 11[10]
                                                            = 11[6 + 4]
                                                 = 11[ Sum of the digits of the chosen number  
4.                                      Chosen number    =  17
                        Number with reversed digits     = 71
                                                        Sum   =  17 + 71 = 88
Now,                                                    88    = 11[8]
                                                                 = 11[1+7]
                                                   = 11[Sum of the digits of the chosen number]
                          

Question
CBSEENMA8002731

Check what result would have been if Sundaram had chosen the numbers shown. 1.17 2.21 3.96 4.37.

Solution

1.                           Chosen number  = 17
             Number with reversed digits  =  71
                                    Difference  = 71 - 17 = 54
                                                   = 9 x [6]
        
2.                                    Chosen number = 21
                       Number with reversed digits = 12
                                             Difference  = 21 - 12 = 9
                                                            = 9 x [1]
           = 9 x [Difference between the digits of the chosen number (2 - 1 = 1)]

3.                      Chosen number = 96
         Number with reversed digits = 69
                               Difference  = 96 - 69 = 27
                                              = 9 x [3]
= 9 x [Difference between the digits of the chosen number (9 - 6)]

4.                                  Chosen number = 37
                    Number with reversed digits  = 73
                                            Difference = 73 - 37 = 36
                                                          = 9 x [4]
      = 9 x [Difference between the digits of the chosen number (7 - 3 = 4)]