+91-9350504919 support@wiredfaculty.com
Wired Faculty Logo
Wired Faculty Logo Wired Faculty

Sponsor Area

Exponents and Powers

Question
CBSEENMA8002605
Wired Faculty App

Find the multiplicative inverse of the following.
(i) 2–4            (ii) 10–5         (iii) 7–2    (iv) 5–3   (v) 10–100

Solution

(i) The multiplicative inverse of 2–4 is 24.

(ii) The multiplicative inverse of 10–5 is 105
(iii) The multiplicative inverse of 7–2 is 72.

(iv) The multiplicative inverse of 5–3 is 53.

(v) The multiplicative inverse of 10–100 is 10100.

Question
CBSEENMA8002608
Wired Faculty App

Simplify and write in exponential form.

(–2)–3 x (–2)–4

Solution

(–2)–3 x (–2)–4  = (-2)(-3) + (-4)                  [∵ space space straight a to the power of straight m cross times straight a to the power of straight n equals straight a to the power of straight m plus straight n end exponent]
                              = WiredFaculty or  fraction numerator 1 over denominator left parenthesis negative 2 right parenthesis to the power of 7 end fraction

Question
CBSEENMA8002609
Wired Faculty App

Simplify and write in exponential form.

p3 x p–10

Solution

p3 x p–10= left parenthesis straight p right parenthesis to the power of 3. space left parenthesis negative 10 right parenthesis end exponent space equals left parenthesis straight p right parenthesis to the power of negative 7 end exponent or space fraction numerator 1 over denominator left parenthesis 10 right parenthesis to the power of 7 end fraction

Question
CBSEENMA8002611
Wired Faculty App

Simplify and write in exponential form.

32 x 3–5 x 36

Solution

32 x 3–5 x 36 = 3 to the power of 2 plus left parenthesis negative 5 right parenthesis plus 6 end exponent space equals space 3 to the power of 8 minus 5 end exponent equals 3 cubed

Sponsor Area

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation