Sponsor Area

Binomial Theorem

Question
CBSEENMA11014353

Solve 24x < 100, when

(i) x is a natural number

(ii) x is an integer

Solution

24x < 100 rightwards double arrow fraction numerator 24 straight x over denominator 24 end fraction less than 100 over 24 space rightwards double arrow space straight x less than 25 over 6 space or space straight x less than 4 1 over 6
∴ (i)  When space space straight x space element of space straight N comma space straight x space equals space 4 comma space 3 comma space 2 comma space 1
∴  Solution set is WiredFaculty
(ii)  When straight x space element of space straight Z comma space straight x space equals space 4 comma space 3 comma space 2 comma space 1 comma space 0 comma space minus 1 comma space minus 2 comma space minus 3......
The solution set is open curly brackets.... comma negative 3 comma space minus 2 comma space minus 1 comma space 0 comma space 1 comma space 2 comma space 3 comma space 4 close curly brackets

Question
CBSEENMA11014354

Solve -12x > 30, when

(i) x is a natural number.            (ii) x is an integer.

Solution

-12x > 30
rightwards double arrow      fraction numerator negative 12 straight x over denominator negative 12 end fraction less than fraction numerator 30 over denominator negative 12 end fraction                                            (∵ -12 < 0)
rightwards double arrow         WiredFaculty
∴ (i) When straight x space element of space straight N, there is no solution
∴ The solution set is straight ϕ.
(ii)    When WiredFaculty
         The solution set is WiredFaculty

Question
CBSEENMA11014355

Solve 5x – 3 < 7, when

(i) x is an integer.              (ii) x is a real number.          

Solution

5x – 3 < 7
               5x – 3 < 7 rightwards double arrow 5x < 10 rightwards double arrow x<2
∴    (i) When space space straight x element of space straight Z comma space straight x space equals space 1 comma space 0 comma space minus 1 comma space minus 2 comma space........
           The solution set is open curly brackets.... comma space minus 3 comma space minus 2 comma space minus 1 comma space 0 comma space 1 close curly brackets
      (ii) When straight x space element of space straight R comma space space straight x less than 2 space or space straight x space element of space left parenthesis negative infinity comma space 2 right parenthesis
∴      The solution set is space space left parenthesis negative infinity comma space 2 right parenthesis

Question
CBSEENMA11014356

Solve 3x + 8 > 2, when

(i) x is an integer.              (ii) x is a real number.          

Solution

               3x + 8 > 2
rightwards double arrow              3x > 2 - 8 rightwards double arrow 3x > - 6 rightwards double arrow x > -2
∴  (i) When space space straight x element of space straight Z comma             
          x = -1, 0, -1, 2, 3, ........
          The solution set is open curly brackets negative 1 comma space 0 comma space 1 comma space 2 comma space 3 comma......... close curly brackets
    (ii)  When straight x space element of space straight R space rightwards double arrow space straight x greater than negative 2 space space or space straight x space element of space left parenthesis negative 2 comma space infinity right parenthesis
           The solution set is WiredFaculty